Finding the sum of an array y by passing an array to a function using pointer C++ code example

 

Compiler: Visual C++ Express Edition 2005

Compiled on Platform: Windows XP Pro SP2

Header file: Standard

Additional project setting: Set project to be compiled as C++

Project -> your_project_name Properties -> Configuration Properties -> C/C++ -> Advanced -> Compiled As: Compiled as C++ Code (/TP)

Other info: none

To do: Finding the total of an array y by passing an array to a function using pointer in C++ programming

To show: How to calculate the sum of array element using a function and a pointer in C++ programming

 

// a program to find the total values of an array y by passing an array to a function using pointer

#include <iostream>

using namespace std;

 

#define n 7

 

// function prototype

int get_total(int*, int);

 

int main(void)

{

int total, y[n]={6,9,2,4,5,23,12};

cout<<"\nCalling function get_total(y, n),";

cout<<"\nBy bringing along the value of y, an array";

cout<<"\nfirst address and n = 7, an array size.";

cout<<"\nAn array name, is the pointer to the";

cout<<"\n1st element of an array\n\n";

// function call, pass along the pointer to the first array element and the array size, and the

// return result assign to variable total

total = get_total(y, n);

 

cout<<"\nSum of the 7 array elements is "<<total<<endl;

 

return 0;

}

 

// the function definition

int get_total(int *ptr, int x)

{

int i, total = 0;

 

// traverse all the array elements

for(i=0; i<x; i++)

{

// displays the array content, pointed by pointer...

cout<<*(ptr+i)<<" ";

// do the summing up of the array elements

total += *(ptr+i); //total=total + *(ptr+i);

}

// return the result to the calling program

return total;

}

 

Output example:

 

Calling function get_total(y, n),

By bringing along the value of y, an array

first address and n = 7, an array size.

An array name, is the pointer to the

1st element of an array

6 9 2 4 5 23 12

Sum of the 7 array elements is 61

Press any key to continue . . .

 

 

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