C++ STL set, upper_bound() program example

Compiler: Visual C++ Express Edition 2005

Compiled on Platform: Windows XP Pro SP2

Header file: Standard

Additional library: none/default

Additional project setting: Set project to be compiled as C++

Project -> your_project_name Properties -> Configuration Properties -> C/C++ -> Advanced -> Compiled As: Compiled as C++ Code (/TP)

Other info: none

To do: How to use the C++ upper_bound() to return an iterator to the first element in a set with a key that is greater than a specified key in C++ programming

To show: Using the C++ set, upper_bound() to return an iterator to the first element in a set with a key that is greater than a specified key in C++ programming

// C++ STL set, upper_bound()

#include <set>

#include <iostream>

using namespace std;

int main(void)

{

// set container

set <int> st1;

// iterators

set <int> :: const_iterator st1Iter, st1PIter, st1QIter;

// insert data into st1 set

st1.insert(9);

st1.insert(12);

st1.insert(20);

st1.insert(13);

st1.insert(40);

// print the data

cout<<"st1 set data: ";

for(st1Iter = st1.begin(); st1Iter != st1.end(); st1Iter++)

cout<<" "<<*st1Iter;

cout<<endl;

st1QIter = st1.upper_bound(20);

cout<<"The first element of st1 set with a key greater than 20 is: "<<*st1QIter<<endl;

st1QIter = st1.upper_bound(11);

// if no match is found for the key, end( ) is returned

if(st1QIter == st1.end())

cout<<"The st1 set doesn't have an element with key greater than 40 is: "<<*st1QIter<<endl;

// the element at a specific location in the set can be found by using a dereferenced iterator addressing the location

st1PIter = st1.begin();

st1QIter = st1.upper_bound(*st1PIter);

cout<<"The first element of st1 set with a key greater than that of the initial element of st1 set is: "<<*st1QIter<<endl;

return 0;

}

Output examples:

st1 set data: 9 12 13 20 40

The first element of st1 set with a key greater than 20 is: 40

The first element of st1 set with a key greater than that of the initial element of st1 set is: 12

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