Displaying arrays' elements and their respective indices in various format

 

 

Compiler: Visual C++ Express Edition 2005

Compiled on Platform: Windows 2003 Server Standard Edition

Header file: Standard

Additional library: none/default

Additional project setting: Set project to be compiled as C

Project -> your_project_name Properties -> Configuration Properties -> C/C++ -> Advanced -> Compiled As: Compiled as C Code (/TC)

Other info:

To do: Printing arrays' elements and their respective indices in various formats using pointer notation

To show: How to use array's subscript and pointer notations in C programming

 

 

// Using subscript and pointer notations with arrays

#include <stdio.h>

 

void main(void)

{

int i, offset, b[] = {10, 20, 30, 40};

// set bPtr to point to array b

int *bPtr = b;

 

printf("So many notations?????....\n");

// ....separating code in multiple lines

printf("Array b printed with: \n"

"Array subscript notation\n");

 

for(i=0; i<=3; i++)

printf("b[%d] = %d\n", i, b[i]);

 

printf("\nPointer/offset notation where \n"

"the pointer is the array name\n");

for(offset = 0; offset <=3; offset++)

printf("*(b + %d) = %d\n", offset, *(b + offset));

 

printf("\nPointer subscript notation\n");

for(i=0; i<=3; i++)

printf("bPtr[%d] = %d\n",i,bPtr[i]);

 

printf("\nPointer/offset notation\n");

for(offset = 0; offset <=3; offset++)

printf("*(bptr + %d) = %d\n", offset, *(bPtr + offset));

}

 

Output example:

 

So many notations?????....

Array b printed with:

Array subscript notation

b[0] = 10

b[1] = 20

b[2] = 30

b[3] = 40

Pointer/offset notation where

the pointer is the array name

*(b + 0) = 10

*(b + 1) = 20

*(b + 2) = 30

*(b + 3) = 40

Pointer subscript notation

bPtr[0] = 10

bPtr[1] = 20

bPtr[2] = 30

bPtr[3] = 40

Pointer/offset notation

*(bptr + 0) = 10

*(bptr + 1) = 20

*(bptr + 2) = 30

*(bptr + 3) = 40

Press any key to continue . . .

 

 

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